0=-2x^2-2x-4

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Solution for 0=-2x^2-2x-4 equation: 



0=-2x^2-2x-4

We move all terms to the left:

0-(-2x^2-2x-4)=0

We add all the numbers together, and all the variables

-(-2x^2-2x-4)=0

We get rid of parentheses

2x^2+2x+4=0

a = 2; b = 2; c = +4;
Δ = b2-4ac
Δ = 22-4·2·4
Δ = -28
Delta is less than zero, so there is no solution for the equation

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